Bitcoin is the other side-angle-side inequality | Euclid's Elements Book 1 Prop 25

2 years ago
6

Assume:

- BA = ED
- AC = DF
- FE < CB

Claim: EDF < BAC

Proof method: contradiction

Suppose claim is false. Then BAC <= EDF.

Then either BAC == EDF or BAC < EDF. We proceed by falsifying both
branches.

Claim: BAC != EDF.

Proof method: contradiction.

Assume BAC == EDF. Then by side-angle-side congruence, CB = FE, which
we assumed to be false.

Claim: BAC !< EDF.

Proof method: contradiction.

Assume BAC < EDF. Then by the previous proposition, BC < EF, which we
assumed to be false.

We have eliminated both branches of EDF !< BAC. Therefore EDF < BAC.

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