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Cho hàm số y=(x^2 + mx+m^2 -2m-4)/(x-2) (1). Tìm m để đồ thị hàm số đã cho có hai điểm cực trị
7 months ago
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Cho hàm số y=(x^2 + mx+m^2 -2m-4)/(x-2) (1). Tìm m để đồ thị hàm số đã cho có hai điểm cực trị và hai điểm cực trị cách đều đường thẳng 2x+y+1 = 0
#ToanLop12
#CucTri
#DaoHam
#Derivative
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