3456% efficiency

I had a little help with this one. The one wire system can be rather "simple"

You
help me figure this out, my input trigger is 12v pulsed at 116 hertz square wave at 1% cycle pulse, I measure the input pulse to be 4ma. the output pulse is 132 UF discharging at 100v 3 times a second. what is the loss or the gain of the system?

ChatGPT
To determine the gain or loss of your system, we need to calculate the energy input and output per unit time and then compare them. Let's break down each part of your setup.

Energy Input Calculation
Input Voltage (V): 12 volts
Input Current (I): 4 mA (0.004 Amperes)
Frequency (f): 116 Hertz
Duty Cycle: 1%
The power (P) consumed by your input can be calculated using the formula P = V × I. However, considering the duty cycle and frequency, the average power over a cycle will be reduced.

The duty cycle of 1% means that the pulse is 'on' for only 1% of each cycle. Since the frequency is 116 Hz, each cycle lasts 1/116 seconds. Therefore, the 'on' time per cycle is (1/116) * 0.01.

Now, the average power over one second (which includes 116 of these cycles) can be calculated as follows:
Energy Output Calculation
Capacitance (C): 132 μF (0.000132 Farads)
Voltage across the capacitor (Vc): 100 volts
Discharge Frequency: 3 times per second
The energy (E) stored in a capacitor is given by the formula E = 0.5 × C × Vc². This energy is discharged 3 times per second.

Here's how it goes:

Total Energy Discharged per second equals E multiplied by Discharge Frequency.
Here, E represents the energy stored in the capacitor.
To find E, we use the formula:
E equals 0.5 times C times Vc squared.
C is the capacitance, and Vc is the voltage across the capacitor.

Now, combining these:
Total Energy Discharged per second equals 0.5 times C times Vc squared, all multiplied by the Discharge Frequency.

Comparing Input and Output Energy:
Finally, to find the loss or gain of the system, we compare the energy input per second with the energy output per second:
If the energy output per second is greater than the energy input per second, the system has a gain.
If the energy output per second is less than the energy input per second, the system has a loss.

The calculations yield the following results:

Average Power Input: Approximately 0.05568 Watts (or Joules per second, since 1 Watt = 1 Joule/second).
Total Energy Output: Approximately 1.98 Joules per second.
These results indicate that the system is outputting significantly more energy per second (1.98 Joules) than it is consuming (0.05568 Joules).

You
so what is the percentage gain?

ChatGPT
To calculate the percentage gain, you need to compare the output energy with the input energy. Here, the output energy is 1.98 Joules per second, and the input energy is 0.05568 Joules per second. Let's calculate the percentage gain:

The formula for percentage gain is:
Percentage Gain equals (Output Energy per second minus Input Energy per second) divided by Input Energy per second, all multiplied by 100 percent.
This formula is a handy tool to evaluate the efficiency of an energy system.

Let's put in our experiment's data:

Our Output Energy is 1.98 Joules per second.
Our Input Energy is 0.05568 Joules per second.
Using these values in our formula:

Percentage Gain equals (1.98 minus 0.05568) divided by 0.05568, all multiplied by 100 percent.

The calculated percentage gain of your system is approximately 3456%. This suggests that the system is outputting energy at a rate more than 34 times higher than the input energy rate.
However, as mentioned earlier, such a high energy gain is extraordinary and not typically observed in conventional systems.

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