Mostre que mdc (a,b) = mmc (a,b) se, e somente se a=b | PROFMAT aritmética mínimo múltiplo comum e
9 months ago
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Mostre que mdc (a,b) = mmc (a,b) se, e somente se a=b e mmc (a^n,b^n) = mmc (a,b) ^n Aritmética Profmat
Aritmética e Indução. PROFMAT) Exercícios de Aritmética para o PROFMAT
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